Question

12 gram of 12 carbon contains Avogadro's number of carbon atoms. a) give the Avogadro number .b) the mass of 2 moles of ammonia gas is 1)2 gram 2) 1.2 into 10 raise to 22 gram 3)17 gram 4) 34 gram c) calculate the volume of ammonia gas produced at STP when 140 gram of Nitrogen gas reach reacts with 30 gram of hydrogen gas (atomic mass n= 14u ,H= 1u)

Answer 1

a) 6.022*10^23

b) 34g

c)224L [10 moles]

Answer 2

Answer:

a) 6.023 x 10²³

b) 34 gram

c) 224 litres.

Explanation:

a) We know that Avogadro's number  = 6.023 x 10²³

b) We know that number of moles present in an element

= the mass provided / the total mass of the element

or, 2 = mass provided / 17

we know mass of ammonia (NH₃) = 14 + (3 x 1) = 17

or, mass provided = 2 x 17 = 34 g

c) We know that number of moles of N₂ = 140 / 28 = 5 moles

and number of moles of H₂ = 30 / 2 = 15 moles

the reaction is s follows :

N₂ + 3H₂ ➞ 2NH₃

we can see that 15 moles of H₂ produces 10 moles of ammonia

Therefore volume of ammonia at STP  = 22.4 x 10 = 224 litres.

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