12) h.C.F of two numbers is 6 and also their difference is 6. The numbers are
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Dear friend,
Let numbers be 12x and 12y where x and y are both co-prime numbers
|12x - 12y| = 12∣12x−12y∣=12
12 |x - y| = 1212∣x−y∣=12
|x - y| = \frac{12}{12} = 1∣x−y∣=
12
12
=1
So there can be many possibilities,
x = 2 , y = 1
So they can be 24 and 12.
x = 3 , y = 2
So they can be 36 and 24.
x = 5 , y = 4
So they can be 60 and 48.
Hope it helps !!!
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