Question

12 ) How much force is required to stop a vehicle
of mass
1000 kg running on a road with coefficient
of friction between the tyres and the road is 0.4?​

Answer 1

Answer:

Force due to friction is mgu where m is the mass, g is gravity, and I is the coefficient of friction. That gives you 1000*9.8*0.4 which equals 3920.Jul 3, 2020

Answer 2

Step-by-step explanation:

Force due to friction is mgu

where,m is the mass,

g is gravity,

I is the coffecient of friction,

Hence,1000×9.8×0.4=3920

Force=3920N