Question

12. If 4x+y = 256 and 4y = 16, what will be the value of x?
a) 2
c) 4
b) 8
d) 16
If 4^(x+y)=256 and 4^y=16 , what is the value of x?

Answer 1

Answer:

●If 4x+y = 256 and 4y = 16, what will be the value of x?

4y = 16

4y = 16 y = 16/4

4y = 16 y = 16/4 = 4

By substituting the value of y in this equation-

4x+y = 256

4x+4 = 256

4x = 256-4

4x = 252

x = 63

●If 4^(x+y)=256 and 4^y=16 , what is the value of x?

4^(x+y)=256

4^(x+y) = 4^4

x+y = 4

y= 4-x -------1st equation

4^y=16

4^y = 4^2

y = 2 ----------2nd equation

By substituting the value of y in 1st equation-

y = 4-x

2 = 4-x

2-4 = -x

-2 = -x

2 = x

therefore, x = 2 and y = 2