12. If A = 45°, verify that:
(i) sin 2A = 2 sin Acos A
(ii) cos 2A = 2 cos A-1=1-2 sin A
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Answered by
2
Answer:
i) sin 2A = 2 sin A cos A
L.H.S. = sin 2A
= sin(2 x 45)
= sin 90°
= 1
R.H.S. = 2sin A cos A
= 2 sin 45° cos45°
= 2 x 1/√2 x 1/√2
= 2 x 1/2
= 1
L.H.S. = R.H.S.
Hence, verified
Answered by
2
Answer:
your second question is wrong .It will be cos² nd sin²
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