Question

(a) On a day with no wind, a fountain in Switzerland propels 30 000 kg of water per minute to a height of 140 m. Calculate the power used in raising the water.
(b) The efficiency of the pump which operates the fountain is 70%.Calculate the power supplied to the pump.
(c) On another day, a horizontal wind is blowing. The water does not rise vertically. Explain why the water still rises to a height of 140 m.

Answer 1

Answer:

Explanation:

MARK MY ANSWER AS BRANLIEST

given

m=30,000kg

H=140m

Time=1minute

poweR=work/time

Work=mgh

=30,000*9.8*140

=41,160,000 j

So,

Power=work/time

=41,160,000/60

=686,000 watt

Answer 2

Answer:

the height will not increase nor decrease because the wind blows in a horizontal direction