12. If a and b are the zeros of the polynomial x ^ 2 + x - 2 find the value of (i) * a ^ 3 + b ^ 3; (ii) * 1/a + 1/b - ab
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We know that for any quadratic polynomial
p(x)=ax
2
+bx+c where a
=0
Let α,β be the zeroes of the polynomial p(x)
Then, α+β=
a
−b
and αβ=
a
c
Now, given that
p(x)=x
2
−4
3
x+3
So, we have α+β=4
3
αβ=3
Using above values we get
α+β −(αβ)=4
3
−3
Step-by-step explanation:
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