12. If a, ß are zeroes of x^2- px - 7, then a^2+ B^2 is
(1 Point)
p^2+ q^2
p^2+ 24
2p^2+ q^2
none of these
Answers
Answered by
0
Answer:
p²+14
Step-by-step explanation:
Given a=1 b= -p c= -7
alpha+beta= -b/a =p
(alpha)(beta)=c/a = -7
alpha²+beta²=(alpha+beta)²-2(alpha)(beta)
=(p)²-2(-7)
=p²+14
Similar questions