Math, asked by SirNV, 5 hours ago

12. If a, ß are zeroes of x^2- px - 7, then a^2+ B^2 is
(1 Point)
p^2+ q^2
p^2+ 24
2p^2+ q^2
none of these​

Answers

Answered by nishtirumalaraju
0

Answer:

p²+14

Step-by-step explanation:

Given a=1 b= -p c= -7

alpha+beta= -b/a =p

(alpha)(beta)=c/a = -7

alpha²+beta²=(alpha+beta)²-2(alpha)(beta)

=(p)²-2(-7)

=p²+14

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