Question

12
If x = 2t3 and y = 3t2 then value dy/dx
is

Answer 1

Explanation:

dx/dt = 2x3t^2 = 6t^2

dy/dt = 6t

dy/dx = 1/t

Answer 2

Answer:

x = 2 t^3, y = 3 t^2

dx/ dt = 2 *3 t^2

dx/dt = 6 t^2

=> dy / dt = 3 *2 t

dy / dt = 6 t

Now,

dy/ dx = dy/dt/ dx/dt = 6t/6t^2

=> dy / dx = 1/ t