Question

12. In A ABC, angle A= angle C and BM bisects angle ABC. Prove that BM
is perpendicular to AC


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Answer 1

Answer:

Here, in ∆ABC.

angle A = angle B

therefore, it is an isosceles ∆triangle.

and in an isosceles ∆ ,the sides opposite to the equal angles are equal..

i.e. AB=BC

if BM bisect ∆ABC .°.

in ∆BMC and ∆BMA,

BM=BM. ----1

ANGLE A = ANGLE C. ----2

and,AB=BC

Hence, ∆BMA =~ ∆BMC..

proved...

Answer 2

Answer:

BM=BM. ----1

ANGLE A = ANGLE C. ----2

and,AB=BC

Step-by-step explanation: