12. In right APQR, ZP= 90', PQ = 6 cm. RP= 8 cm. Find the value of cos Rand cos Q.
Answers
Answered by
1
Step-by-step explanation:
PQ = 8 cm
QR = 6 cm
PR = ?
∠PQR = 90°
According to Pythagoras Theorem,
(PR)2 = (PQ)2 + (QR)2
PR2 = 82 + 62
PR2 = 64 + 36
PR2 = 100
∴ PR = √100 = 10 cm
(ii) Given :
PR = 34 cm
QR = 30 cm
PQ = ?
∠PQR = 90°
According to Pythagoras Theorem,
(PR)2 = (PQ)2 + (QR)2
(34)2 = PQ2 + (30)2
1156 = PQ2 + 900
1156 - 900 = PQ2
256 = PQ2
∴ PQ = 16 cm
hope it will help you
please mark me as Brainliest
Attachments:
Similar questions