Question

* 12. In the figure, if angle QRS = 100° and
ray Qp ray ST.
What can be the possible values of x and y
provided x and y are obtuse angles.​

Answer 1

may be my answer helps you

Given PQ∣∣ST and ∠PQR=100

o

and ∠RST=110

o

Draw AB line parallel to line PQ and ST at point R

ThePQ∣∣AR and line QR cut at point R

Then ∠PQR+∠QRA=180

o

⇒100

o

+∠QRA=180

o

⇒∠QRA=180−100=80

0

The ST || RB and line SR cut at point R

Then∠RST+∠SRB=180

o

⇒110+∠SRB=180

⇒∠SRB=180−110=70

o

Then ∠QRA+∠QRS+∠SRB=180

o

∴80+∠QRS+70=180⇒QRS=180−70−80=30

o

Answer 2

Step-by-step explanation:

one of the possible values can be x=120degree and y=140degree