Question

12. In the figure, O is the centre of the bigger
circle and AC is its diameter. Another
circle with AB as diameter is drawn. If
AC = 54 cm and BC = 10 cm, find the
area of the shaded region.
​

Answer 1

Answer:

it is too easy too solve.

step by step;

we know that AC-BC=AB which is diameter of small circle.

54cm-10cm=44cm diameter

&

Radius of AB is=diametre/2

Radius of AB is=44cm/2

=22cm

THEN AREA IS EQUAL TO:

1. πr^2=22/7*22*22
2. =1521.14 cm square
3. area of smaller circle is 1521.14

Diameter of bigger circle is 54cm

then its radius will be d/2=54cm/2

=27cm

area=πr^2

1. πr^2=22/7*27*27
2. =2291.14cm square

NOW AREA OF SHADED REGION IS

1. area of (bigger circle - smaller circle) = area of shaded region
2. 2291.14cm-1521.14cm= 770cm square

• the area of shaded region is 770cm square.
• Is I am correct then tell me