Question

12. In the given figure, AB is the diameter of the
circle with centre O.
A
С
32° 0
90
B
D
If ZADC = 32°, find angle BOC​
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Answer 1

Answer:

angle BOC = 116°

Step-by-step explanation:

We join A and C. AC is the chord of the circle which subtends an angle 32° at D on the major arc. The angle subtended by the same chord AC at the center will be twice the angle subtended at D= 2×32=64°

Therefore angle AOC = 64°

AOB is the diameter of the circle.

Therefore angle AOB = 180°

angle BOC = angle AOB - angle AOC

= 180°-64°

= 116°

Answer 2

Answer:

angle BOC =116

Step-by-step explanation:

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