12. In the given figure, find sec a.
AB 4 cm
CD 12 cm
BC
3 cm
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1
Answer:
13/12
Step-by-step explanation:
In ABC
AB*2+BC*2=AC*2(Pythagoras theorem)
so AC=√16+9=√25=5
now In ACD
AD*2=12*12+5*5=169
AD=13
now sec A=Hypotenuse/base
so secA=13/12
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