12. Ir 3tanA = 4. then the value of
3 sin A +2cos.
3 sin A -2cos.
is
please tell in easy way
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Step-by-step explanation:
3tanA=4
tanA=4/3
tanA=BC/AB=4/3=K
BC/4=AB/3=K
BC/4=K AB/3=K
BC=4K AB=3K
AC²=AB²+BC²
AC²=4K²+3K²
AC²=16K²+9K²
AC²=25K²
AC=√25K²
AC=5K
SinA=3K/5K=3/5
CosA=4K/5K=4/5
3SinA+2Cos
=3(3/5)+2(4/5)
=9/5+8/5
=9+8/5
=17/5
3SinA-2Cos
=3(3/5)-2(4/5)
=9/5-8/5
=9-8/5
=1/5
HOPE YOU GET IT
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