Question

12. Ir k-1, k + 3 and 3k-1 are three consecutive terms of a AP, find the value of k.
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Answer 1

Answer:

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We know that :

In AP

$\bold\green{d=second\:term\:-\:first \:term=}$ $\bold\green{third\:term-\:second\:term}$

➡

$(k + 3) - (k - 1) = (3k - 1) - (k + 3)$

➡

$k + 3 - k + 1 = 3k - 1 - k - 3$

➡

$4 = 2k - 4$

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$8 = 2k$

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$k = \frac{8}{2}$

➡

$k = 4$

$hope \: \:it \: helped \: u \:$