12) जर x = 3 हे ka-10x+3= 0 या समीकरणाचे एक
मूळ
असेल, तर 'k'ची किंमत किती ?
Answers
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Answer:
k = 27/a
Step-by-step explanation:
ka - 10 *3 +3 =0
ka -30+ 3 = 0
ka = 27
k = 27/a
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