Math, asked by hk5in2, 1 year ago

12 किमी लम्बे वृताकार मार्ग पर तीन धावक A.B.C एक ही बिन्द से तथा एक ही दिशा में क्रमश: 3
किमी/घंटा 7 किमी/घंटा तथा 13 किमी/घंटा की चाल से चलते हैं। कितने घंटे के उपरान्त वे
एक साथ मिलेंगे?
(8) 16 घंटे
(6)12 घंटे (6) 24 घंटे (d) 28 घंटे​

Answers

Answered by knjroopa
3

Step-by-step explanation:

Three runners a, b and c run along a circular path of 12 km long with speeds 3km/hr, 7km/hr, 13km/hr. They start their race from the same point for the same destination. After how much time they will meet again  

  • So the long circular route is 12 km
  • Now speed = distance / time  
  • So time taken by A = 12 / 3 = 4 hours
  • Time taken by B = 12 / 7 hours
  • Time taken by C = 12 / 13 hours
  • So we have 4, 12/7, 12/13
  • Now LCM of Numerator / hcf of denominator.
  •    So lcm of 4,12, 12 will be  
  •    Factors are  
  •       4 = 2 x 2
  •      12 = 2 x 3 x 2
  •       12 = 2 x 3 x 2
  • So we get 2 x 2 x 3 = 12
  • Now hcf of 7,13 will be 1
  • So 12 / 1 = 12 hours.
  • So they will meet again after 12 hours.

Reference link will be

https://brainly.in/question/18447314

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