Math, asked by shlokpatel77, 10 months ago

12 litres of a solution contains 33 ×1÷3 % of acid.

How many litres of water is to be added to
reduce the acid percentage to 20%?​

Answers

Answered by neerajchandra797
6

Step-by-step explanation:

in 12 litre solution 4 litre = acid

now 4 =(12+water) ×20%

20= 12 + water

water = 8 litre

is required quantity to be added.

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