Math, asked by rahulroypfb, 5 months ago

12 men can complete a work in 8 days. 16 women can complete the same work in 12 days. 8 men and 8 women started working and worked for 6 days. How many more men are to be added to complete the remaining work in 1 day?​

Answers

Answered by snehamdawn05
0

Answer:

To complete the work =8 x12= 96 man-hours are required.

To complete the same work= 16 x 12= 192 woman- hours are required.

So 1 man- hour= 192/96= 2- woman -hours.( Or)

1 woman -hour= 1/2 man-hours

8 men+ 8 women= (8 +8/2)= 12 man - hours.

If they work 6-days the amount of work done= 12 x 6= 72 man - hours.

The remaining work consists of =(96–72)= 24

If 24- man-hours work is to be finished in 1- day then 24 men will be required.

Already 8 men + 8 women are working which is equivalent to 12- men.

So more men required = (24–12)= 12

Answered by abhilash7995
0

Answer:

To complete the work =8 x12= 96 man-hours are required.

To complete the same work= 16 x 12= 192 woman- hours are required.

So 1 man- hour= 192/96= 2- woman -hours.( Or)

1 woman -hour= 1/2 man-hours.

8 men+ 8 women= (8 +8/2)= 12 man-hours.

If they work 6-days the amount of work done= 12 x 6= 72 man - hours.

The remaining work consists of =(96–72)= 24

If 24- man-hours work is to be finished in 1- day then 24 men will be required.

Already 8 men + 8 women are working which is equivalent to 12- men.

So more men required = (24–12)= 12

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