12 men or 15 women can do a piece of work in 21 days. Find the number of days required to complete the same work by 6 men and 10 women
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Answered by
4
Answer:
12 men = 21 days
1 man = 252 days
1 man in 1 day = 1/252 of the work
6 men = 6/252 = 1/42 of the work
15 women = 21 days
1 woman = 315 days
1 woman in 1 day =1/315 of the work
10 women in 1 day = 10/315 = 2/63 of the work
so 6men + 10 women in 1 day = 1/42 +2/63 = 7/126= 1/18
ANSWER 18 days
Answered by
2
Answer:
15
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