Question

12 ml of 0.25N H,SO, is neutralised with 15mlof sodium hydroxide solution on titration, then the
normality of NaOH solution is
​

Answer 1

Answer:

(V * N)(NaOH) = (V * N)(H2SO4) NNaOH = (V * N)(H2SO4)/VNaOH 12 * 0.25/15 = 0.2N

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