12. Show that x=1 is a root of the polynomial 3x^3– 4x^2+7x – 6
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Answer:
Given that x= 1
P(x) = 3x^3 - 4x^2 + 7x - 6
p(1) = 3(1)^3 - 4(1)^2 + 7(1) - 6
p (1) = 3- 4 + 7 -6
p(1) = -1-6+ 7
p(1) = -7+7
p(1) = 0
Hence x=1 is a root of the polynomial 3x^3 - 4x^2 + 7x - 6.
Answered by
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Answer:
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