Question

12. Solve the following systems of equations
ons
2.x
1/
a) 2x + 3y = 9; 3.x + 4y = 5

Answer 1

\begin{lgathered}2x + 3y = 9 \\ 2x = 9 - 3y \\ x = \frac{9 - 3y}{2} \\ 3x + 4y = 5 \\ 3( \frac{9 - 3y}{2} ) + 4y = 5 \\ 27 - 9y + 8y = 10 \\ - y = 10 - 27 \\ y = 17 \\ 2x + 3(17) = 9 \\ 2x = 9 - 51 \\ 2x = - 42 \\ x = - 21\end{lgathered}2x+3y=92x=9−3yx=29−3y3x+4y=53(29−3y)+4y=527−9y+8y=10−y=10−27y=172x+3(17)=92x=9−512x=−42x=−21 

Answer 2

Step-by-step explanation:

Given,

2x + 3y = 9 Equation 1

3x + 4y = 5 Equation 2

Multiply equation 1 by 3,

6x + 9y = 27

Multiply equation 2 by 2,

6x + 8y = 10

To eliminate x, Subtract the equations.

From subtracting you get,

y = 17

From equation 1,

2x + 3y = 9

2x + 51 = 9

2x = - 42

x = - 21