Question

12 th term of on A.P. 16,11,6,.........​

Answer 1

Answer:

given that .

$\star$ first term = 16

$\star$ common difference = 11 - 16 = -5

$\star$ nth term = 12

THEN ACCORDING TO THE QUESTIONS

$\huge\boxed{an = a + ( n - 1) d}$

a12 = 16 + (12 - 1) (-5)

a12 = 16 + 11 ×(-5)

a12 = 16 - 55

a12 = -39

$\huge\boxed{a12 = -39 }$