Question

12. The area of the triangle
formed by the points
A(4,0),B(10,0) and C(4,3) is
*​

Answer 1

Answer:

By distance formula

AB=UNDERROOT (10-4)^2+UNDERROOT(0-0)^2

AB=UNDERROOT(6)^2+0

AB=UNDERROOT 36

AB=6

BC=UNDEROOT(4-10)^2+UNDERROOT(3-0)^2

BC=UNDERROOT(-6)^2+UNDERROOT(3)^2

BC=UNDERROOT36+9

BC =UNDERROOT45=3UNDERROOT5

CA=UNDERROOT(4-4)^2+(3-0)^2

CA=UNDERROOT 0 + 9

CA=UNDERROOT9

CA=3

AREA OF TRIANGLE =1/2×B×H

1/2×6×3

=9