12. The digit in the tens place of a two-digit number is three times that in the units place.
digits are reversed, the new number will be 36 less than the original number. Find the
original number. Check your solution.
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Answer:
let the digit in the one's place be x
Then, the digit in the tens place = 3x
The no. formed is = 10 x 3x + x= 31x
If the digits are reversed, the new number formed is 10 X x + 3x = 13x
13x = 31x - 36
x = 2
The original no. = 31 X 2 = 62
Step-by-step explanation:
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