12. The internal bisectors of ZB and C of AABC meet at 0. If B+C = 100°, then
BOC =
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Answer:
BOC =90
explained in image
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Answer:
Angle BOC =130°
Step-by-step explanation:
Used concept:-
In a ∆ABC ,the angle bisectors of B and C meeta at O then angle BOC=90°+(angleA/2)
=>90°+80°/2
=>90°+40°
=>130°
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