Question

12. The mass of a lead piece is 115 g. When it is
immersed into a measuring cylinder, the water
level rises from 20 mL mark to 30 mL mark,
Find :
(i) the volume of the lead piece,
(ii) the density of the lead in kg m-?.
Ans. (i) 10 cm (ii) 11500 kg m-?​

Answer 1

★Given:-

• The mass of a lead piece is 115 g.
• When it is  immersed into a measuring cylinder, the water  level rises from 20 ml mark to 30 ml.

★To find:-

• The volume of the lead piece,
• The density of the lead in kg/m³

★Solution:-

Given that,when it is  immersed into a measuring cylinder, the water  level rises from 20 ml mark to 30 ml.

Hence,

• Initial volume = 20ml
• Final volume = 30ml

Volume of lead piece:-

➜Final volume - initial volume

➜30 - 20

➜10ml

We know,

1 ml = 1cm³

10ml = 10cm³

Therefore,

➜Volume of lead piece is 10cm³.

Using the formula,

✦Density = Mass/volume

Putting values,

➜Density = m/v

➜115/10

➜11.5g/cm³

We know,

1g/cm³ = 1000kg/m³

11.5g/cm³ = 11500kg/m³

Hence,

The density of lead is 11500kg/m³.

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