Question

12. The sum of the 4th and 6th terms of an A.P is 42 and the sum of 3rd
and 9th terms is 52. Find the first three term of the A.P
R. Arun​

Answer 1

Step-by-step explanation:

a+3d+a+5d=42

2a+8d=42

2(a+4d)=42

a+4d=21

a+4d =5th term=21

a+8d+a+2d=2a+10d

2(a+5d)=52

a+5d=26=6th term

6th term - 5th term

d=5

a+4d=21

a+4(5)=21

a=21-20

(i)a=1

(ii)a+d=6

(iii)a+2d=11

first 3 terms = 1,6,11

Answer 2

Answer:

AP is : 1, 6, 11, 16.........