Question

12. Two angles of a right - angled triangle are in the ratio 1:5. Find each angle of
the triangle​

Answer 1

$\huge\mathfrak{\underline{\underline{Answer:-}}}$

As we know , two angles of right angled triangle are in the ratio 1:5.

We need to find the angles of the triangle.

A Right angled triangle measures 90°

Let the angles be 1x and 5x.

According to problem ,

1x + 5x = 90°

or 6x = 90°

or x = 90/6

or x = 15

The angles are :-

1x = 1×15

= 15°

5x = 5×15

= 75°

Answer 2

Answer:

$\huge\mathfrak{Answer:( 15\:,75)}$

Given that :

• Two angles of a right - angled triangle are in the ratio 1:5.

To find :

• each angle of
• each angle ofthe triangle

According to the Question:-

=> Let the ∠N be 90°as

 

ΔMNO is a right angled triangle.. 

Let the ∠M be 1x

as mentioned in the question..

Let the ∠O be 5x

as mentioned in the question..

The sum of all the angles of a triangle is equal to 180°.

$\huge\boxed{Therefore,}$

1x + 5x + 90° = 180°

6x + 90° = 180°

6x = 180° - 90°

6x = 90°

x = 90/6

x = 15°

∠M = 1x = 1 x 15 = 15°

∠N = 90°

∠O = 5x = 5 x 15 = 75°