12. Two cross roads, each of width 5 m, run at right angles through the centre of a
rate of 200 per m.
rectangular park of length 70 m and breadth 45 m and parallel to its sides. Find
the area of the roads. Also find the cost of constructing the roads at the rate of
105
per
m2
Answers
Answered by
2
Answer:
width =5 m
length of first parallel road 70 m
area of first road 70×5=350 sq.m
length of second road 45 m
area of second road =45×5=225 sq.m
area of the common part of cross road with 5 m width that lies at the
center of the park 5×5 = 225 sq.m
area of roads = area of first road +area of second cross road−common area
=(350+225)−25
=575−25
=550sqm
cost of the construction per sq.m =Rs.105
total cost =550×105=Rs 57750
Answered by
0
Answer:
➥57,750.
Step-by-step explanation:
➥see in attachment
➥hope its helps you .
Attachments:
Similar questions