Math, asked by Anonymous, 8 months ago

12. Verify that : x3 + y3 + z3 - 3xyz = 1/2(x + y + z)
[(x - y)2 + (y - z)2 + (z - x)2]​

Answers

Answered by barikaparna067
2

Answer:

ANSWER

We have, L.H.S.=x

3

+y

3

+z

3

−3xyz

=(x+y+z)(x

2

+y

2

+z

2

−xy−yz−zx) [by poynomial identity]

=

2

1

(x+y+z)(2x

2

+2y

2

+2z

2

−2xy−2yz−2zx)

=

2

1

[(x+y+z)(x−y)

2

+(y−z)

2

+(z−x)

2

]

Step-by-step explanation:

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