Question

12. When 0º < theta < 90°, solve the following equations:
(1) 2 cos2(theta) + sin(theta) - 2 = 0
(ii) 3 cos theta = 2 sin2 (theta)
(iii) sec2(theta) - 2 tan(theta) = 0
(iv) tan2(theta)= 3 (sec(theta) - 1).​

Answer 1

Answer:

MATHS

Prove with the help of trigonometric Identities.

2sin

2

θ+4sec

2

θ+5cot

2

θ+2cos

2

θ−4tan

2

θ−5csc

2

θ=1

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ANSWER

2sin

2

θ+4sec

2

θ+5cot

2

θ+2cos

2

θ−4tan

2

θ−5cosec

2

θ

=2(sin

2

θ+cos62θ)+4(sec

2

θ−tan

2

θ)+5(cot

2

θ−cosec

2

θ)

=2×1+4×1+5×(−1)

=2+4−5

=1=RHS