Question

12. When a car driver travelling at a speed
of 10 m/s applies brakes and brings the car
to rest in 20 s, then the retardation will be: *
m
(1 Point)
+ 2 m/s2
0 - 2 m/s2
- 0.5 m/s2
+0.5 m/s2​

Answer 1

Answer:

this is the answer to the question

Answer 2

Answer:

Step-by-step explanation:

TIME(T)=20 SEC

INITIAL VELOCITY(U)=10m/s

FINAL VELOCITY(V)=0

RETARDATION=(U-V)/T

                        =10-0/20

                        =10/20

                         =+0.5m/s²