Question

find the value of a cube minus 27 b cube if a minus 3 b = - 6 and ab = - 10​

Answer 1

hope it helps you.... to get your answer

Answer 2

Given :- a - 3b = -6 & ab = -10

Find :- a^3 - 27b^3

Using Identity :-

(a-b)^3 = a^3-b^3-3ab(a-b)

= (a-3b)^3 = a^3-(3b)^3-9ab(a-3b)

= (-6)^3 = a^3-(3b)^3-9(-10)(-6)

= a^3-27b^3 = -216+540

= a^3-27b^3 = 324

Hope my answer will surely helps you...

thnx 4 asking ✌️