Question

12. Write a pair of integers whose product is – 36 and whose difference is 15.
With explained

Answer 1

Answer:

a*b=-36

a-b=15

a=15+b

(15+b)*b=-36

15b+b^2=-36

b^2+15b+36=0

b^2+12b+3b+36=0

b(b+12)+3(b+12)=0

(b+12)(b+3)=0

b= -12 0r -3

a - (-12)=15 or a-(-3)=15

a=3 or a=-12

Answer 2

Answer:

suppose a, b is the integer number.

given that,

ab  = -36

and

if a is greater than b then

a - b = 15

a = 15 + b

from equation 1

(15 + b)b = -36

$b^{2}$ + 15b + 36 =0

(b + 3) (b + 12) = 0

b = -3, = -12;

a - (-3) = 15     a - (-12) = 15

a = 12             a = 3;

(a , b) = (12, -3), (-12, 3)

Step-by-step explanation:

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