Question

12 x+13y=60;13x+12y=40 . solve the equation by simultaneous equation.​

Answer 1

Answer:

The given equations are

12x+13y=29…(i)

13x+12y=21…(ii)

Add (i) and (ii), we get

12x + 13y =29

13x + 12y =21

-------------------

25x + 25y =50

25(x+y) = 50

x + y = 2

Answer 2

The value of x = -8 and y = 12 when two linear equation are 12x + 13y = 60 and 13x + 12y = 40.

Given that,

The two linear equation are 12x + 13y = 60 and 13x + 12y = 40

We have to solve the two linear equation and find the x and y values.

We know that

Take the equation

12x + 13y = 60 ---------->equation(1)

13x + 12y = 40 ---------->equation(2)

Multiply equation(1) by 13

13(12x + 13y = 60)

156x + 169y = 780  ----------->equation(3)

Multiply equation(2) by 12

12(13x + 12y = 40)

156x + 144y = 480  ----------->equation(4)

Subtract equation(3) and equation(4)

169y - 144y = 780 - 480

25y = 300

y = 12

Then substitute the y = 12 in equation(1)

12x + 13y = 60

12x + 13(12) = 60

12x + 156 = 60

12x = 60 - 156

12x = -96

x = -8

Therefore, The value of x = -8 and y = 12 from the linear equation

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