Question

12 x ki power 3 + 24 x ki power 2 + 12 x is equal to zero solve for x

Answer 1

Bonjour!

$= > 12 {x}^{3} + 24 {x}^{2} + 12x = 0 \\ \\ = > 12 {x}^{3} + 12 {x}^{2} + 12 {x}^{2} + 12x = 0 \\ \\ = 12 {x}^{2} (x + 1) + 12x(x + 1) = 0 \\ \\ = > (x + 1)(12 {x}^{2} + 12x) = 0 \\ \\ = > 12x(x + 1)(x + 1) = 0 \\ \\ = > {(x + 1)}^{2} = \frac{0}{12x } \\ \\ = > x = - 1$

Hope this helps...:)

Answer 2

12x^3+24x^2+12x=0
12x^2+24x+12=0
x^2+2x+1=0
x=[(-2)+-{4- 4×1×1}^1/2] /2
x= -1

hope this will help you.
thanks.