please solve it....hurry!!!!
Attachments:
Anonymous:
hi
Answers
Answered by
8
heya man , here is the answer !!
consider , 3^lnx = 2^lny
taking log on both side ,,
(lnx)(ln3) = (lny)(ln2)
=> lny = (lnx)(ln3)/ln2
consider , 2x^ln2 = 3y^ln3
ln2(ln2+lnx) = ln3(ln3+lny)
(ln2)²+ln2×lnx = (ln3)²+ln3×lny
ln2²+ln2×lnx = (ln3)²+ln3× (lnx)(ln3)/ln2
-ln2 = lnx
=> 1/2
lny = (lnx)(ln3)/ln2 = 1/2ln3/ln2 = ln√3/2
lny = ln√3/2
hope that helps
## himanshu Jha ✌✌
consider , 3^lnx = 2^lny
taking log on both side ,,
(lnx)(ln3) = (lny)(ln2)
=> lny = (lnx)(ln3)/ln2
consider , 2x^ln2 = 3y^ln3
ln2(ln2+lnx) = ln3(ln3+lny)
(ln2)²+ln2×lnx = (ln3)²+ln3×lny
ln2²+ln2×lnx = (ln3)²+ln3× (lnx)(ln3)/ln2
-ln2 = lnx
=> 1/2
lny = (lnx)(ln3)/ln2 = 1/2ln3/ln2 = ln√3/2
lny = ln√3/2
hope that helps
## himanshu Jha ✌✌
Similar questions
English,
7 months ago
Physics,
7 months ago
Computer Science,
7 months ago
Math,
1 year ago
Social Sciences,
1 year ago
Math,
1 year ago