please solve it....hurry!!!!
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Anonymous:
hi
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heya man , here is the answer !!
consider , 3^lnx = 2^lny
taking log on both side ,,
(lnx)(ln3) = (lny)(ln2)
=> lny = (lnx)(ln3)/ln2
consider , 2x^ln2 = 3y^ln3
ln2(ln2+lnx) = ln3(ln3+lny)
(ln2)²+ln2×lnx = (ln3)²+ln3×lny
ln2²+ln2×lnx = (ln3)²+ln3× (lnx)(ln3)/ln2
-ln2 = lnx
=> 1/2
lny = (lnx)(ln3)/ln2 = 1/2ln3/ln2 = ln√3/2
lny = ln√3/2
hope that helps
## himanshu Jha ✌✌
consider , 3^lnx = 2^lny
taking log on both side ,,
(lnx)(ln3) = (lny)(ln2)
=> lny = (lnx)(ln3)/ln2
consider , 2x^ln2 = 3y^ln3
ln2(ln2+lnx) = ln3(ln3+lny)
(ln2)²+ln2×lnx = (ln3)²+ln3×lny
ln2²+ln2×lnx = (ln3)²+ln3× (lnx)(ln3)/ln2
-ln2 = lnx
=> 1/2
lny = (lnx)(ln3)/ln2 = 1/2ln3/ln2 = ln√3/2
lny = ln√3/2
hope that helps
## himanshu Jha ✌✌
:-)
sorry i didnt get the 2nd last step how did u get -ln2= lnx there???
ya
option c) is right answer
1/
1/2
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