12(xsquare+7x)square-8(xsquare+7x)(2x-1)-15(2x-1)square factorize the following
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Let
uv=x2+7x=2x−1u=x2+7xv=2x−1
Then, the expression becomes:
12u2−8uv−15v2=12u2−18uv+10uv−15v2=6u(2u−3v)+5v(2u−3v)=(6u+5v)(2u−3v)12u2−8uv−15v2=12u2−18uv+10uv−15v2=6u(2u−3v)+5v(2u−3v)=(6u+5v)(2u−3v)
Now, putting u,vu,v back in:[Math Processing Error]
\lb6(x2+7x)+5(2x−1)\rb\lb2(x2+7x)−3(2x−1)\rb=\lb6x2+42x+10x−5\rb\lb2x2+14x−6x+3\rb=(6x2+52x−5)(2x2+8x+3)\lb6(x2+7x)+5(2x−1)\rb\lb2(x2+7x)−3(2x−1)\rb=\lb6x2+42x+10x−5\rb\lb2x2+14x−6x+3\rb=(6x2+52x−5)(2x2+8x+3)
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