120gm of urea are present 5l solution the active mass of urea is
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Moles of urea = 120 g / (60 g/mol) = 2 mol
Active mass = Moles of solute / Volume of solution in litre
= 2 mol / (5 Litre)
= 0.4 mol/L
Active mass of solution is 0.4 mol/L
Active mass = Moles of solute / Volume of solution in litre
= 2 mol / (5 Litre)
= 0.4 mol/L
Active mass of solution is 0.4 mol/L
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