Math, asked by roopabai1974, 5 months ago

121(x³y²z²+x²y³z²-x²y²z³)÷11(x²y²z²)

Answers

Answered by AshutoshPriyadarshan

0

Answer:

11(x+y-z)

Step-by-step explanation:

121(x³y²z²+x²y³z²-x²y²z³)÷11(x²y²z²)

= 11(x+y-z)

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Answered by luckyborra707

1

I answered it clearly if it helps you pls hit thanks button and mark me as brainliest

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