121p^2 +16q^2-88pq factorise it
Answers
Answered by
14
Answer:
121p²+16q²-88pq
(11p)²+(4q)²-2(11p)(4q)
(11p-4q)²
Answered by
2
Answer:
Simplifying
121p2 + 16q2 + -88pq = 0
Reorder the terms:
-88pq + 121p2 + 16q2 = 0
Solving
-88pq + 121p2 + 16q2 = 0
Solving for variable 'p'.
Factor a trinomial.
(11p + -4q)(11p + -4q) = 0
Similar questions
CBSE BOARD XII,
4 months ago
Science,
4 months ago
Math,
4 months ago
English,
9 months ago
Math,
9 months ago