Science, asked by abcd8672, 10 months ago

121p^2 +16q^2-88pq factorise it

Answers

Answered by rounaq47

14

Answer:

121p²+16q²-88pq

(11p)²+(4q)²-2(11p)(4q)

(11p-4q)²

Answered by suchita46

2

Answer:

Simplifying

121p2 + 16q2 + -88pq = 0

Reorder the terms:

-88pq + 121p2 + 16q2 = 0

Solving

-88pq + 121p2 + 16q2 = 0

Solving for variable 'p'.

Factor a trinomial.

(11p + -4q)(11p + -4q) = 0

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