Question

{(125)^-4 × (256)^-3/2}^-1/6​

Answer 1

Answer:

Heya mate your answer in the attacment below

Step-by-step explanation:

Answer 2

Answer:

100

Step-by-step explanation:

So ur question is :

$[(125)^{(-4)}*(256)^{(\frac{-3}{2})}]^{(\frac{-1}{6})}$

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So lets simplify them first :

$5^3=125\\\\\\256^{\frac{-3}{2}}=(\sqrt{256})^{-3}=(16)^{-3}$

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Now just put the values in place :

$=[(5^3)^{-4}*(16)^{-3}]^{\frac{-1}{6}}\\\\\\=[(5)^{-12}*(16)^{-3}]^{\frac{-1}{6}}\\\\\\=[(5)^{-12}*^{\frac{-1}{6}}]*[(16)^{-3}*^{\frac{-1}{6}}\\\\\\=[(5)^{-2*-1}]*[(16)^{-1*{\frac{-1}{2}}$

$=5^2*(16)^\frac{1}{2}}\\\\\\=5^2*\sqrt{16} \\\\\\=5^2*4\\\\\\=25*4\\\\\\=100$