125 / 5 power 3 whole power 2 how to solve these exponents
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Answered by
4
(125/5^3)^2
(5^3/5^3)^2
(1)^2
1
(5^3/5^3)^2
(1)^2
1
Answered by
5
(125/5³)²
=125²/(5³)²
=125²/5³*²
=125²/5⁶
=15625/15625
=1
=125²/(5³)²
=125²/5³*²
=125²/5⁶
=15625/15625
=1
ammunazriya:
thank u pradinidhi for marking it brainliest
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