125*8*883+117*25*40 solve by distributive property.
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Answered by
182
Hi ,
if a,b ,c are integers
ab + ac = a ( b+ c ) is distributive property.
125 × 8 × 883 + 117 × 25 × 40
= ( 125 × 8 ) × 883 + 117 × ( 25 × 40 )
= 1000 × 883 + 117 × 1000
a = 1000 , b = 883 , c = 117
= 1000 ( 883 + 117 )
= 1000 × 1000
= 1000000
I hope this helps you.
:)
if a,b ,c are integers
ab + ac = a ( b+ c ) is distributive property.
125 × 8 × 883 + 117 × 25 × 40
= ( 125 × 8 ) × 883 + 117 × ( 25 × 40 )
= 1000 × 883 + 117 × 1000
a = 1000 , b = 883 , c = 117
= 1000 ( 883 + 117 )
= 1000 × 1000
= 1000000
I hope this helps you.
:)
Answered by
43
1000*883+117*1000
1000*(883+117)
1000*1000
1000000
1000*(883+117)
1000*1000
1000000
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