125 drops are charged to a potential of 200 volt these drops collapse to form a big drop determine the change in potential and energy
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Dear Students,
◆ Answer with explaination -
Sum total of all potentials initially is -
V' = n.V
V' = 125 × 220
V' = 27500 V
Potential of bigger drop is -
V" = V.n^(2/3)
V" = 220 × 125^(2/3)
V" = 220 × 25
V" = 5500 V
Change in total potential is -
∆V = V" - V'
∆V = 5500 - 27500
∆V = -22000 V
Therefore, total potential decreased by 22000 V.
Change in energy of drops can't be calculated because capacitance is not given.
Hope that was helpful...
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