Question

125 gallons of a mixture contains 20% water. What amount of additional water should be added such that water content be raised to 25%?​

Answer 1

Answer:

8.33 GAL of additional water.

Step-by-step explanation:

125 gal of mixture contains 25 gal water + 100 gal of other, there fore one can solve the problem by using this equation where x = gals of water needed to make the other 75 % of the mixture.

100/x = 75/25, x = 33.3 gals

therefore ; 33.33 gals - 25 gals = 8.33 gal (additional water needed to make mixture 25% water.

8.33 gal of additional water will make the mixture 25% water (by volume)

Proof; the final mix is 133.33 total gal….. of that 33.33 gal of it is water . 33.33 gal is 25% of 133.33 gal.